divide by 8 counter circuit

[jumong]

penge naman po kung meron kayo.

[zer0w1ng]

You need 3 toggle flipflops to do this and cascade into ripple counters. Input clock is feed to the first T input. The Q to the T input of the next flipflop and so on.

Like this:

CLK o---TQ---TQ---TQ---o divide by 8 output

[jumong]

T-flip flop lang pala  . puede din kayang gumamit ng D flip-flop?

[zer0w1ng]

Yes. You can convert D flipflops to T. Just connect the Q' to the D input.

[spidamang]

Question lang: Can a 7490 decade counter set to reset at 8 do the trick too?   

[zer0w1ng]

Any binary counter does. Q2 will output divide by 8. But a decade counter (div by 10), may not.  I am not familiar of 7490 but if it can be modified as a binary counter (resets at power of 2 count). Then it will do divide by 8.

[spidamang]

7490 is a BCD counter actually. The thought just occurred to me to use one because I'm planning to make a BCD display clock that displays time in BCD format using ordinary LEDs and 7490 is ideal. I'm just waiting for my local parts store to stock it.

I'll verify the div by 8  with a 7490 later at home. 

[spidamang]

Well it counts to 8 and resets but kailangan mo pa yatang gumamit ng gates across D0,D1,D2 para magamit ang 8th count na output.

Oh well. Live and learn 

[jumong]

salamat spidamang