200W atx power supply how to boost current output?

[lapigut!]

^ compute the power in the resistor. kung 10A, 10 * 10 * 1 = 100W resistor ang kailangan. actually, pwede namang mababa, tapos may relay. once naka-build up na 'yung motor ng torque, pwede niya nang i-short 'yung resistor. 'yung starting current ang malamang na malaki diyan kaya nade-detect nung PSU as overload at pinapatay.

di ko makuha ung design...basic relay design ba yan with switching transistor??

[lapigut!]

sis rd, bakit po 10 * 10 * 1?

[rdpzycho]

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--+--/\/\/\/\/\--+--[load (compressor)]
  |              |
  +-----[NO]-----+

kapag sinaksak 'yung compressor, dadaan muna sa resistor 'yung current para limited 'yung starting current. ngayon after some set delay time (or after sensing a set current), pwede nang i-close 'yung contacts ng relay para 'di na dumaan sa resistor. short period lang siya kaya 'di masisira 'yung resistor kung mababa ang power rating.

in some very big power supplies with very big capacitor banks, ginagamit 'to (thermistors may burn in the high currents), pero ang hinihintay bago i-close 'yung relay is a set voltage, meron ng charge 'yung capacitors at 'di na malaki 'yung surge.

sis rd, bakit po 10 * 10 * 1?

sample lang 'yan for a 1 ohm resistor (which will limit the output of the 12V rail to 12A in short circuit condition, typical of a starting motor). for 2.2 ohms then that's 220W.

[lapigut!]

ahh...parang tunnel ung relay...ok ok...getz ko na...hehehe thanks sis rd... mtry nga bukas...


+beauty points sayo sis!