kay bang gumawa ng 300w na audio booster

[danny]

pina pa compute ko lng sa kanila sa "ohms law"  mga paps.heheheh 

 
musta na paps?
bakit nde ka na nakaka online sa
umaga? ano na nangyari sa connection mo?

[THXneo]

musta na paps?
bakit nde ka na nakaka online sa
umaga? ano na nangyari sa connection mo?

badtrip nga paps.
la na ko mabilis na connection sa ofc.
naputol na free wifi sa kabilang ofc  e.heheheh.nilagyan na ng password.
ni ko na mahack ang code.
e2 sa bahay na lng me nakaka browse.

[tdh7700]

pina pa compute ko lng sa kanila sa "ohms law"  mga paps.heheheh 

hehehe losssser yaya

[THXneo]

hehehe losssser yaya

  ano un?

[gie62]

di kinaya ng powers ng calculator ko, hehehe

[cmdr73]

 ehh paano sa input supply ang base nila. base sa EE#46 ehh ang voltage output ng power amps ang babasehan hindi sa input power supply

[zer0w1ng]

The output voltage of the amp is dependent on its power supply.

And high power amps like the rockford fosgate has a step-up SMPS built-in so that the power supply is raised to the proper voltage.
I posted here about this (link on details, construction and schematics) on a thread awhile ago. Just search for it.

[danny]

The output voltage of the amp is dependent on its power supply.

And high power amps like the rockford fosgate has a step-up SMPS built-in so that the power supply is raised to the proper voltage.
I posted here about this (link on details, construction and schematics) on a thread awhile ago. Just search for it.

this is correct.
I agree

[gie62]

ehh paano sa input supply ang base nila. base sa EE#46 ehh ang voltage output ng power amps ang babasehan hindi sa input power supply

nahugot ko tuloy yung ee46 ko sa baul ah. sir nakalagay dun sa article na ang output ng amp ay  related sa power supply. kaya kung mababa lang ang output voltage ng power supply hindi mo mapapataas ang wattage ng amp. pansinin mo yung mga high wattage na amp, matataas ang output voltage ng power supply.

[danny]

nahugot ko tuloy yung ee46 ko sa baul ah. sir nakalagay dun sa article na ang output ng amp ay  related sa power supply. kaya kung mababa lang ang output voltage ng power supply hindi mo mapapataas ang wattage ng amp. pansinin mo yung mga high wattage na amp, matataas ang output voltage ng power supply.

 e d punong puno ng agiw na iyan
at mga gagamba
hehehehe   

[cmdr73]

papaka hirap pa kayo ehh.  di abangan na niyo yung output voltage ng amps saka na ninyo compute madali pa. mas accurate ang computation kasi lahat ng losses bawas na kung baga. neto na yan po ang nasusulat ! sa EE#46 sa biblia ng alexan.   Marami sa audio circuits na meron clang power allowance sa input supply.

yung formula or computation ko is base sa output voltage hindi po sa input voltage.

Power = output voltage square/ohms of speaker = multiply by 0.707 to get RMS wattage

ito na po ang tunay na power output ng amps based sa nabasa ko sa EE ng alexan

[gie62]

e d punong puno ng agiw na iyan
at mga gagamba
hehehehe   

hehehehe

[zer0w1ng]

Power = output voltage square/ohms of speaker = multiply by 0.707 to get RMS wattage
ito na po ang tunay na power output ng amps based sa nabasa ko sa EE ng alexan

The maximum output voltage of the speaker is the power supply voltage minus Vcesat voltage of the transistors. And is always dependent of the supply.

Again I am sorry but the formula is also WRONG.  You have to multiply first with square root of 2 (0.707) the voltage before squaring it and dividing the speaker impedance.

Prms = (0.707*Vpeak)^2/R

where Vpeak is the peak voltage which is half of the peak-to-peak voltage.

Also take note that measuring the speaker output voltage directly with an AC VOM will give you the RMS voltage. Similarly, reading a 220VAC on the power outlet is really 620V peak to peak.

[gie62]

papaka hirap pa kayo ehh.  di abangan na niyo yung output voltage ng amps saka na ninyo compute madali pa. mas accurate ang computation kasi lahat ng losses bawas na kung baga. neto na yan po ang nasusulat ! sa EE#46 sa biblia ng alexan.   Marami sa audio circuits na meron clang power allowance sa input supply.

yung formula or computation ko is base sa output voltage hindi po sa input voltage.

Power = output voltage square/ohms of speaker = multiply by 0.707 to get RMS wattage

ito na po ang tunay na power output ng amps based sa nabasa ko sa EE ng alexan

tama yung nasa EE46. hindi mo napansin dun sa fig.2 yung 10v supply ay yun na yung rms voltage at yung 14.14v yun yung peak.
kaya ang computation dun ay P=10v^2/8ohms=12.5Wrms, P=14.14v^2/8ohms=25Wpeak.
subukan mong gamitin yang formula mo kung makukuha mo ang 12.5Wrms.
tama yung sinasabi ni zer0wing.

[danny]

tama yung nasa EE46. hindi mo napansin dun sa fig.2 yung 10v supply ay yun na yung rms voltage at yung 14.14v yun yung peak.
kaya ang computation dun ay P=10v^2/8ohms=12.5Wrms, P=14.14v^2/8ohms=25Wpeak.
subukan mong gamitin yang formula mo kung makukuha mo ang 12.5Wrms.
tama yung sinasabi ni zer0wing.

baka pwedeng pa post naman nung EE46 topic na
pinag uusapan nyo, para naman
makita din ng ibang members yung discussion
ano bang amplifier yun?
 

[gie62]

baka pwedeng pa post naman nung EE46 topic na
pinag uusapan nyo, para naman
makita din ng ibang members yung discussion
ano bang amplifier yun?
 

sir, reference article about amplifier. wala kong digi cam o scanner kaya di ko ma post..

[♪ ♫ ♫ ♪ ♪ ♪ ♫ ♫ ♫]

Yon kasing maximum peak value ng half cycle ng sine wave output ng amps ay about 80% lang ng + or - ng power supply before it clips....mosfets can go as high as 95% of the supply voltage before it clips....it is a peak to peak value so dapat convert it to effective power that is rms value to have a real power of the amps.

Hoax talaga yong 13.8 supply tapos ang lalaki ng power output.....transformerize boosters uses 13.8V for both positive and negative cycle of the sine wave amps output, if u uses a mosfet it can attain as high as 26Vp-p (13V positive half-cycle and 13V negative half-cycle), divide by sqrt of 2 nasa mga 18Vrms lang talaga ang very effecient transformerize boosters. 

You can only boost the power by using 4 or 2 ohms speaker load (parallels) to pump more currents... but usually it blows up the power driver when playing an uneven loudness music, i mean heavy rock or deep bass musics....since speaker impedance will go almost shorted   

SMPS is a good solution for hi wattage 8 ohms loads...

[TinTopHack]

If we just use the continuous rated power of 500W x 4 @ 4 ohms as basis for the calculation - the power that the 12V battery must deliver is 500W x 4 = 2000W. At this power the current drain from the battery is 2000W/12V = 166.67Amps - Kaya ito sang ordinary car battery.
BUT since the spec says 500W into 4 ohms (x 4) rms, the voltage needed to deliver 500W into 4 ohms is SQRT of P x R = SQRT (500 x 4) = 44.72Vrms. Since this is Vrms the peak to peak voltage is 45V x 1.414 x 2 = 128V. Therefore the 12V supply from the battery MUST be stepped up to at least 128VDC (assuming a unipolar supply is used) so that a 45V rms voltage output can be achieved . This step up function is achieved by using switchmode inverters.

At 500W into 4 ohms the output current is 125A rms. You will need a lot of high current/high voltage power transistors to generate this. Combine all that with the special power supply required plus the brand name - it is no wonder that the price tag is the same as the price tag of a high end car.
You can use the same  method to calculate voltages and current needed to operate at 7500W x 2 @ 1-Ohm bridged RMS.